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How many Kilograms of Pure water to be added to 100 Kilograms of a 30% saline solution to make it a 10% saline solution.

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Best answer
Correct option is A)
Let x be the weights, in Kilograms, of pure water to be added. Let y be the weight, in Kilograms, of the 10% solution.

Hence x+100=y
Let us now express the fact that the amount of salt in the pure water (which is 0) plus the amount of salt in the 30% solution is equal to the amount of salt in the final saline solution at 10%.
0 + 30% 100 = 10%y

Now by substituting the value of y in terms of x, we get the equation as,
30% 100 = 10%(x+100)

30×100=10(x+100)

3000=10x+1000

10x=2000

x=200
Answer x=200 Kilograms.
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