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How many 5-digit numbers can be formed using the digits 1, 2, 5, 7, and 8 in each of which no digit is repeated?

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Solution:

The given 5 digits (1, 2, 5, 7 and 8) should be arranged among themselves in order to get all possible 5-digit numbers.

The number of ways for doing this can be done using the factorial.

5! = 5 × 4 × 3 × 2 × 1 = 120

Answer: Therefore, the required number of 5-digit numbers is 120.
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